Physics 10164 - Homework #2
Due Mon Feb 1 at the beginning of class
Solve the following problems on your own paper. Please:
- Show all work.
- Put a box around your final answer to each problem.
- Be sure proper significant figures (SF) used for all answers.
- Separate all solutions with a horizontal line on your paper.
- A random selection of four problems will be graded for 25 points each.
- Solutions for suggested odd problems can be seen by following links.
- Solutions for assigned problems will be linked from this page after the due date.
Chapter 16
- #26
- Simple application of equation 16.8, similar to suggested problem #28. Be sure to work in mks units.
- #32
- Similar to problem 52 in chapter 15 from homework #1. Gravity, tension and the electric force must all be considered.
- #34
- Similar to suggested problems 33 and 35. We will do some like these in class. Use the dielectric strength as an indicator of the electric field that exists when the charge is at its maximum. Don't forget to take the dielectric constant of polystyrene into account as well as the new electric field strength in part b.
- #44 #44 (cont)
- Start by finding the equivalent capacitance for the entire circuit (see examples 16.7, 16.8 and 16.9 for guidance on how to do this). We will do similar problems together in class.
- #50
- The plate separation is not needed here. Use equation 16.8 where the potential difference in a uniform field is simply Ed (Electric field * distance between plates). Note that capacitance is inversely related to distance (equation 16.9), so distance cancels out.
- Suggested problems from chapter 16:
-
#25,
#27,
#28,
#29,
#30,
#31,
#33,
#35,
#36a #36b,
#37,
#38a #38b,
#39a #39b,
#40a #40b,
#45,
#46a #46b,
#49a #49b,
#51,
#54,
#55,
#56a #56b,
#59
Chapter 17
- #4
- First figure out how many Coulombs flow past a point in an hour given a rate of 0.15 Coulombs/sec.
- #14
- Assume the cross-sectional area is circular. Work in mks units!
- #28
- Be careful converting area units. Note that 0.450 mm^2 = 0.000000450 m^2 (0.450 x 10^(-6) m^2).
- #34
- First, use Power = Energy/time to find the energy in Joules, then convert to cents. See examples 17.5 and 17.6 for guidance.
- #40
- You have the information to calculate R and Ro. Use these pieces to solve for the temperature difference.
- #44
- Similar to 34.
- Suggested problems for chapter 17:
-
C1,
C2,
C3,
C4,
C5,
C6,
C7,
C8,
C9
C10,
C11,
#1,
#2a #2b,
#3,
#5,
#7,
#10,
#11,
#13,
#15,
#16,
#17,
#19,
#20,
#22,
#23,
#24,
#25,
#26,
#27,
#29a #29b,
#33,
#35,
#36a #36b,
#37,
#38,
#39,
#41,
#42,
#43,
#45,
#49,
#50,
#51,
#52a #52b,
#53,
#54